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5x^2+68x+4=0
a = 5; b = 68; c = +4;
Δ = b2-4ac
Δ = 682-4·5·4
Δ = 4544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4544}=\sqrt{64*71}=\sqrt{64}*\sqrt{71}=8\sqrt{71}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(68)-8\sqrt{71}}{2*5}=\frac{-68-8\sqrt{71}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(68)+8\sqrt{71}}{2*5}=\frac{-68+8\sqrt{71}}{10} $
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